ms sql Áú¹®ÇÕ´Ï´Ù..

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7. 세 명 이상의 사원이 참여한 프로젝트의 번호, 이름, 사원의 수를 보이시오.(검색 결과에 사원수열 이름 사용)

 

8. 세 명 이상의 사원이 있는 부서의 사원 이름, 전화번호, 성별, 부서명을 보이시오.


숙제인데..


1~6,9번은 해결을했는데 7번과 8번의 3명이상이라는게 어떤방향인지 감도 안잡히네요..


그룹바이 해빙절 ㎢쨉잘 안되는거 같네요.. 힌트점 부탁드립니다..


밑줄은 기본키입니다.. 쌍 밑줄은 복합키입니다.




Employee                                                               Department


열 이름

데이터타입

널 허용여부

empno

int

허용 안 함

name

varchar(20)

 

phoneno

int

 

address

varchar(20)

 

sex

varchar(20)

 

position

varchar(20)

 

deptno

int

 


열 이름

데이터타입

널 허용여부

deptno

int

허용 안 함

deptname

varchar(20)

 

manager

varchar(20)

 


 


Project                                                                  Works


열 이름

데이터타입

널 허용여부

projno

int

허용 안 함

projname

varchar(20)

 

deptno

int

 


열 이름

데이터타입

널 허용여부

empno

int

허용 안 함

projno

int

허용 안 함

hoursworked

int

 




!...
ªÀº±Û Àϼö·Ï ½ÅÁßÇÏ°Ô.
Ź«Áø 2015-04
Select  work.projno, Project.projename,COUNT(*) as »ç¿ø¼ö
      From work inner join Project
        on work.projno = Project.projno
      group by work.projno,Project.projename
      having COUNT(*) >=3

¶Ç´Â

select z.projno, Project.projename,z.»ç¿ø¼ö
from ( Select  work.projno, COUNT(*) as »ç¿ø¼ö
          From work
          group by work.projno
          having COUNT(*) >=3 ) as z
      inner join Project on z.projno = Project.projno

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¼ÛÁøÇö 2015-04
»ý°¢º¸´Ù group by°¡ À߾ȵ˴ϴÙ..

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 °øºÎ°¡ ´õ ÇÊ¿äÇÏ´Ù´Â ½ÅÈ£ÀΰŠ°°½À´Ï;´Ù..
Ź«Áø 2015-04
with Work  As
(
    Select  '1' As empno, 'p1' as projno, 10 as hoursworked Union All
    Select  '2' As empno, 'p1' as projno, 10 as hoursworked Union All
    Select  '3' As empno, 'p1' as projno, 10 as hoursworked Union All
    Select  '1' As empno, 'p2' as projno, 10 as hoursworked Union All
    Select  '1' As empno, 'p3' as projno, 10 as hoursworked Union All
    Select  '3' As empno, 'p3' as projno, 10 as hoursworked Union All   
    Select  '4' As empno, 'p3' as projno, 10 as hoursworked Union All
    Select  '5' As empno, 'p3' as projno, 10 as hoursworked Union All
    Select  '6' As empno, 'p3' as projno, 10 as hoursworked Union All
    Select  '1' As empno, 'p4' as projno, 10 as hoursworked Union All
    Select  '5' As empno, 'p4' as projno, 10 as hoursworked Union All
    Select  '7' As empno, 'p4' as projno, 10 as hoursworked 
   
)
,Project  As
(
    Select  'p1' as projno, 'Project 1' as projename, 'D1' as deptno  Union All
    Select  'p2' as projno, 'Project 2' as projename, 'D1' as deptno  Union All   
    Select  'p3' as projno, 'Project 3' as projename, 'D1' as deptno  Union All
    Select  'p4' as projno, 'Project 4' as projename, 'D1' as deptno  Union All
    Select  'p5' as projno, 'Project 5' as projename, 'D1' as deptno  Union All
    Select  'p6' as projno, 'Project 6' as projename, 'D1' as deptno
)


Select  work.projno, Project.projename,COUNT(*) as »ç¿ø¼ö
      From work inner join Project
        on work.projno = Project.projno
      group by work.projno,Project.projename
      having COUNT(*) >=3


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