(ÇØ°á¿Ï·á) Äõ¸® Áú¹®µå¸³´Ï´Ù ¤Ð¤Ð

   Á¶È¸ 1801   Ãßõ 0    

 좌측테이블 데이터에서 우측테이블처럼 출력하고자합니다(2번째 행만 없어졌다 보시면됩니다)

Select MAX(Coldate) as ColDate, ColName From Table Group by ColName으로하면




여기까지는 출력해냈습니다.

이러저러해도 뒤엣 3, 4번째 컬럼을 출력하기 어려워 조언을 구합니다 ㅠㅠ



ªÀº±Û Àϼö·Ï ½ÅÁßÇϰÔ.
Àϱ¹ 2022-11
¿øÇÏ½Ã´Â°Ô ¸Â´Â°¡ ¸ð¸£°Ú½À´Ï´Ù.

WITH TEMP_TABLE AS
(SELECT '2022-11-29' COLDATE, '»óǰA' COLNAME, 14 COLWIDTH,  9 COLHEIGHT FROM DUAL UNION ALL
 SELECT '2022-11-28' COLDATE, '»óǰA' COLNAME, 15 COLWIDTH,  9 COLHEIGHT FROM DUAL UNION ALL
 SELECT '2022-11-28' COLDATE, '»óǰB' COLNAME, 52 COLWIDTH, 52 COLHEIGHT FROM DUAL UNION ALL
 SELECT '2022-11-28' COLDATE, '»óǰC' COLNAME, 27 COLWIDTH, 27 COLHEIGHT FROM DUAL UNION ALL
 SELECT '2022-11-28' COLDATE, '»óǰD' COLNAME, 15 COLWIDTH,  9 COLHEIGHT FROM DUAL UNION ALL
 SELECT '2022-11-2E' COLDATE, '»óǰE' COLNAME, 14 COLWIDTH,  9 COLHEIGHT FROM DUAL)
SELECT A.COLDATE, A.COLNAME, A.COLWIDTH, A.COLHEIGHT
  FROM TEMP_TABLE A
 INNER JOIN (
      SELECT COLNAME, MAX(COLDATE) COLDATE
        FROM TEMP_TABLE
        GROUP BY COLNAME
            ) B ON A.COLDATE = B.COLDATE AND A.COLNAME = B.COLNAME;
     
MSSQL 2000¿¡¼­´Â Áߺ¹Ç׸ñÀÌ ³ª¿Í¼­ distinct½á¼­ Á¦°ÅÇϰí È®ÀÎÁßÀÔ´Ï´Ù!
´ëÃæ ÀÌ·±½ÄÀ̸é ÇØ°á °¡´ÉÇÕ´Ï´Ù.
DB Á¾·ù, ¹öÀü¿¡ µû¶ó ´Ù¸¦ ¼ö ÀÖÀ¸´Ï
Äõ¸® Áú¹®Àº »ç¿ëÇÏ´Â DB Á¾·ù ¹öÀüÀ» ±âº»À¸·Î Ç¥±âÇØ¾ß Á¤È®ÇÑ ´äº¯À» ¹ÞÀ» ¼ö ÀÖ½À´Ï´Ù.

SELECT ColDate, ColName, ColWidth, ColHeight
FROM (
SELECT rank() over (partition by ColName order by ColDate DESC) rk
      ,*
FROM Å×À̺í¸í
) lst
WHERE rk=1

µ¥ÀÌÅͰ¡ ¸¹°í ColDate, ColName ÀÌ PK(¶Ç´Â À妽º°¡ ¼³Á¤µÈ)ÀÎ Å×À̺íÀÇ °æ¿ì À§¿¡ Àϱ¹´ÔÀÌ ¼³¸íÇϽйæ¹ýÀ¸·Î ÇØ¾ß
¼Óµµ°¡ ºü¸§´Ï´Ù.
     
±âº»ÀûÀ롃 Á¦°¡ ±ôºýÇß±º¿ä ²ûÂïÇϰԵµ MSSQL 2000À» ¾²°íÀ־ ¿©·¯°¡Áö ³»ÀåÇÔ¼ö°¡ ¾ø½À´Ï´Ù ¤Ð¤Ð
MSSQL 2000 ÀÌ½Ã¸é ¾Æ·¡ Äõ¸®·Î ÇØ°á µÉ µí ÇÕ´Ï´Ù.

WITH TEMP_TABLE AS (
 SELECT '2022-11-29' COLDATE, '»óǰA' COLNAME, 14 COLWIDTH,  9 COLHEIGHT  UNION ALL
 SELECT '2022-11-28' COLDATE, '»óǰA' COLNAME, 15 COLWIDTH,  9 COLHEIGHT  UNION ALL
 SELECT '2022-11-28' COLDATE, '»óǰB' COLNAME, 52 COLWIDTH, 52 COLHEIGHT  UNION ALL
 SELECT '2022-11-28' COLDATE, '»óǰC' COLNAME, 27 COLWIDTH, 27 COLHEIGHT  UNION ALL
 SELECT '2022-11-28' COLDATE, '»óǰD' COLNAME, 15 COLWIDTH,  9 COLHEIGHT  UNION ALL
 SELECT '2022-11-27' COLDATE, '»óǰE' COLNAME, 14 COLWIDTH,  9 COLHEIGHT
)

SELECT ColDate, ColName, ColWidth, ColHeight
FROM (
SELECT ( select count(*)
from TEMP_TABLE counter
where counter.ColName = TEMP_TABLE.ColName -- Partition
and counter.ColDate >= TEMP_TABLE.ColDate  -- Order
) as rk
  ,*
FROM TEMP_TABLE
) lst
WHERE rk=1
     
³î¶øµµ·Ï Á¤»óÀûÀ¸·Î ÀÛµ¿ÇÕ´Ï´Ù ´ë´ÜÇÑ ³»°øÀ̽ʴϴÙ...!


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